RE: [xsl] XSLT/XPath help to resolve definition references in a W SDL XML fi le

[thomas dot cherel at ascentialsoftware dot com]

It almost worked, but it put me on the right track.
What you gave me is not working as in your select, in the key function
second argument, the @aRef is not known in this context (this is not an
attribute of the A element. But I was able to achieve what I wanted doing
the following:

<xsl:key name="Crefs" match="C" use="substring-after(@aRef,':')"/>

 select="A[count(key('Crefs',@name))>0]/B"

The condition in the select of the A element means any A referenced by at
least one C element.

Thanks a lot for the help.

Thomas

-----Original Message-----
From: TSchutzerWeissmann@uk.imshealth.com
[mailto:TSchutzerWeissmann@uk.imshealth.com] 
Sent: Wednesday, September 04, 2002 10:41 AM
To: xsl-list@lists.mulberrytech.com
Subject: RE: [xsl] XSLT/XPath help to resolve definition references in a W
SDL XML fi le


hi Thomas,

> I need some help on pure XSLT/XPath syntax/capabilities. Let's say 
> that I have an XML document looking like that:
> 
> <root>
>   <A name="a1"><B .../></A>
>   <A name="a2"><B .../></A>
>   <A name="a3"><B .../></A>
>   <C aRef="ns1:a1"/>
>   <C aRef="ns2:a2"/>
> </root>
> 
> I want to be able to select all the B element which are under
> the A elements
> referenced by the C element (the A elements for which a 
> C/@aRef attribute
> value, minus the prefix, is equal to the A/@name attribute).
> 

Use a key on the C's:

<xsl:key name="CRefs" match="C" use="@aRef"/>

Then this as your path in <root> context.
 select="A[@name = key('CRefs',substring-after(@aRef,':'))]/B"

Don't know if it works...

Tom
---
"At the first performance I led the attack in person 33 times.
We had three acclamations, four hilarities, two thrilling movements,
four renewals of applause and two indefinite explosions."





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