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RE: How to output partial elements?
- From: Stuart Brown <sbrown at extenza dot co dot uk>
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Date: Tue, 20 Aug 2002 11:04:09 +0100
- Subject: RE: [xsl] How to output partial elements?
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Jem,
> Here is the (style of) input I have:
>
> <record n="1" type="normal">
> <foo> <x>... <y>...</y> ...</x> </foo>
> <bar> <things> ... </things> </bar>
> </record>
> <record n="2" type="normal">
> <foo> <x>... <y>...</y> ...</x> </foo>
> </record>
> <record n="3" type="continuation">
> <bar> <things> ... </things> </bar>
> </record>
> <record n="4" type="normal">
> <foo> <x>... <y>...</y> ...</x> </foo>
> <bar> <things> ... </things> </bar>
> </record>
>
> The problem is <record>s 2 and 3: they need to be
> concatenated. (The 'n'
> attribute is irrelevant: I only put it there for easy reference in
> illustration.)
What you actually want to do here is to include in a type="normal" record
the children of a subsequent type="continuation" record, so something like
this would be required:
<!-- Limit match to normal records only -->
<xsl:template match="record[@type='normal']">
<record n="{@n}">
<!-- Handle the contents of this record -->
<xsl:apply-templates/>
<!-- If the first following sibling is a record of type continuation,
handle its children -->
<xsl:apply-templates
select="following-sibling::record[1][@type='continuation']/*"/>
</record>
</xsl:template>
This assumes that you only ever have one continuation: if there are
potentially more then the XPath will be more complicated.
Hope this helps,
Stuart
>
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