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Re: RE: unique-sequence-numbering
- From: subbu at boltblue dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Wed, 07 Aug 2002 14:31:37 +0100
- Subject: Re: RE: [xsl] unique-sequence-numbering
- References: <F5DVWt76NsOUzdMMCu200006ff7@hotmail.com> <1028040819.3d46a873857d6@www.boltblue.com> <000a01c237de$4333c990$5569aa40@tumeric>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Jeff..
>Short of an elegant solution, here's a simple way to do it:
>
>Step 1: go through your XML file and create another with the student
>elements duplicated as necessary.
>
>Step 2: go through the new file and create the output -- sequence
>numbering is now trivial.
>
Thaz pretty much of what i wanted to do Jeff..was thinking how to do this.and
also if there are any better approaches.. Thanks for your Suggestions.
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sachidanandam..
>
>Always post if soultion is not found in XSL Archives.
>
>http://www.jenitennison.com/xslt/number.html
>Check here.Jeni's solutions is always there .
I dont think you got my question right.. I am pretty much clear with what
position() is used for...
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