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Re: two xml source documents
- From: "Charles Knell" <cknell at onebox dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Thu, 01 Aug 2002 09:58:30 -0700
- Subject: Re: [xsl] two xml source documents
- Reply-to: xsl-list at lists dot mulberrytech dot com
There are two ways to call the document function. This is one I wrote
yesterday which uses a second parameter to specify the path to the document
whose name is the first parameter:
<xsl:template name="Contractor List">
<xsl:variable name="contractors" select="document('contractorList.xml',
'../xml/')" />
<div
<span>Contractors</span>
<span >
<xsl:for-each select="$contractors/contractorList/contractor">
<xsl:sort select="." />
<div name="contractor" id="cont_{@id}" class="normal"><xsl:value-of
select="." /></div>
</xsl:for-each>
</span>
</div>
</xsl:template>
I left out some style attribute information because it takes up space
and is not germane to the question.
>From The XSLT Programmer's Reference 2nd Edition, pg. 466, strictly speaking
the first parameter is a URI which in my case is a file name and the
second parameter is the base-uri which is used to resolve any relative
reference contained in the first parameter. If the first parameter has
no relative references, the second parameter is not necessary.
--
Charles Knell
cknell@onebox.com - email
---- Markus.Lehr@mlp-ag.com wrote:
> Hi everybody, I want to (have to) use two source documents to produce
> one output
> document (fo-document, but I think that doesnt really matter).
>
> I found the document function on the zvon.org XSLT reference list
> but, to be
> honest, I did not really understand how it works. Can anyone give me
> a short
> example?
>
> Thanx in advance
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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