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How to test by nodename if node exsits and not empty
- From: René de Vries <RdVries at PCL-HaGe dot nl>
- To: "xsl-list" <xsl-list at lists dot mulberrytech dot com>
- Date: Thu, 1 Aug 2002 12:08:16 +0200
- Subject: [xsl] How to test by nodename if node exsits and not empty
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
I try to do this: pass a nodename of a childnode of the current node as a
parameter to a template and test if it exists and, if so, if it has a
contents and/or attributes.
My problem is that I can't get the the expression right to count the number
of attributes of $Node. For example count(@*) returns the number of
attributes for the current node and I've tried count($Node/@*),
count($Node[@*]), count($Node/*[@*]) and so on, but the parser complains
that the "expression must evaluate to a node-set".
If I don't count the attributes, <aNode xyz="someinfo"/> would be considered
empty, which I don't want.
WHAT DO I DO WRONG????
my template:
<xsl:template name="TestIfNodeExistsAndIsFilled">
<xsl:param name="NodeName" select="'NoNodeName'"/>
<xsl:variable name="Node">
<xsl:copy-of select="./*[local-name()=$NodeName]"/>
</xsl:variable>
<xsl:if test="(not ($Node)) or (string-length(normalize-space($Node))=0
and count(### what expression? ###))">
<Error>
<Name><xsl:value-of select="$NodeName"/></Name>
<Description>
<xsl:value-of select="$NodeName"/>
<xsl:choose>
<xsl:when test="(not ($Node))">
<xsl:text> not present</xsl:text>
</xsl:when>
<xsl:otherwise>
<xsl:text> not filled</xsl:text>
</xsl:otherwise>
</xsl:choose>
</Description>
</Error>
</xsl:if>
</xsl:template>
Greetings René
{@ @}
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