Re: [xsl] logical and in selection expression possible?

[Joerg Heinicke <joerg dot heinicke at gmx dot de>]

Templates are applied for every root element in the node set returned by 
the key(). If a key('key', 'rulekey1') returns more than one node, "the 
template is being activated twice". With the union operator | you merge 
two node sets, i.e. a node that is member of both node sets is only once 
contained in the unioned node set.

But this seems more or less uninteresting in your case. I assume you 
want to do something completely different. You only want to "collect" 
the nodes and operate with them in one template? Then 
<xsl:call-template> could be the choice while passing the keys to the 
template via a parameter:

<xsl:call-template name="foo">
  <xsl:with-param name="bar" select="key('key', 'rulekey1') | 
key('key', rulekey2')"/>
</xsl:call-template>


<xsl:template name="foo">
  <!-- default value: empty node set -->
  <xsl:param name="bar" select="/.."/>
  ...
</xsl:template>

But a more concrete explanation of your problem can help.

Regards,

Joerg

Alex Reuter wrote:
> Ok, I've run into a bit of a snag.
> When I am passing the union of the nodesets to the applied template, it 
> appears that the template is being activated twice.  I was hoping to be 
> able to access both nodesets at the same time.... unless they are the 
> children of the same parent, is this impossible?
> Thanks,
> Alex
>
>
> > From: David Carlisle <davidc@nag.co.uk>
> > Reply-To: xsl-list@lists.mulberrytech.com
> > To: xsl-list@lists.mulberrytech.com
> > Subject: Re: [xsl] logical and in selection expression possible?
> > Date: Thu, 18 Jul 2002 17:17:29 +0100
> >
> > <xsl:apply-templates select="key('key', rulekey1') and key('key',
> > 'rulekey2') "/>
> >
> > you want | there not and and is a boolean operator so this expression
> > will evaluate to true or false. but a select expression needs a node
> > set.
> >
> >
> > <xsl:template match="rule and rule2">
> >
> > ditto.
> >
> > David

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