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Re: getting text nodes of subtree?
- From: Jarkko dot Moilanen at uta dot fi
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 28 Jun 2002 14:10:07 +0300 (EEST)
- Subject: Re: [xsl] getting text nodes of subtree?
- References: <OF644457FA.8C9F10DF-ONC2256BE6.0038B35F@e-know.net>
- Reply-to: xsl-list at lists dot mulberrytech dot com
This one nearly does it. The result is actually now
aaa bbb ccc BBB AAA bbb ccc BBB
Please educate me =)
Cheers
Jarkko
<xsl:stylesheet xmlns:xsl = "http://www.w3.org/1999/XSL/Transform" version =
"1.0" >
<xsl:output method = "text" />
<xsl:template match = "/" >
<xsl:value-of select = "//a" >
<xsl:value-of select = "text()" />
</xsl:value-of>
<xsl:value-of select = "a/child::*">
<xsl:value-of select = "text()" />
</xsl:value-of>
<xsl:value-of select = "b/child::*">
<xsl:value-of select = "text()" />
</xsl:value-of>
</xsl:template>
</xsl:stylesheet>
Lainaus Jakub.Valenta@Deio.net:
> Hi all,
> how can I get string which contains text nodes of all children of given
> element?
>
> for example what will return
>
> <a>
> aaa
> <b>
> bbb
> <c>
> ccc
> </c>
> BBB
> </b>
> AAA
> </a>
>
> aaabbbcccBBBAAA
>
> br,
>
> Jakub
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
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Researcher/ ITCM *but you spend too much time *
jm60697@uta.fi *reading this sort of trash. *
www.uta.fi/~jm60697 * *
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