[xsl] XPATH as parameter

[Corneanu Dan <cdan at savatech dot ro>]

Hi,

I have a collection of xmls with the following structure:

<?xml version="1.0" encoding="UTF-8"?>
<record>
   <name>Dan</name>
   <city>TM</city>
</record>

and a index.xml file with the URIs of all the record files in my collection:

<?xml version="1.0" encoding="UTF-8"?>
<index>
   <record ref="r1.xml"/>
   <record ref="r2.xml"/>
   <record ref="r3.xml"/>
</index>

I want to make a search on my collection of documents based on an
xpath. The xpath should be a parameter passed to a search.xsl file. The 
problem is
that I don't know how to apply an xpath stored as a parameter variable. 
I have tried like this

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
version="1.0">
   <xsl:output method="xml" indent="yes"/>
   <xsl:param name="xpath">/record/name[contains(../city, 
'TM')]</xsl:param>
  
   <xsl:template match="/index">
       <resultset>
           <xsl:apply-templates select="record"/>
       </resultset>
   </xsl:template>
  
   <xsl:template match="record">       
       <xsl:for-each select="document(@ref)">
           <result>
               <xsl:value-of select="$xpath"/>
           </result>
       </xsl:for-each>
   </xsl:template>
</xsl:stylesheet>

but of course it's not working. Any idea how this can be done?


Thanks.


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