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RE: Newbie: See if a node exists!
- From: Anand Kuppa <AnandK at transputec dot com>
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 7 Jun 2002 14:24:18 +0100
- Subject: RE: [xsl] Newbie: See if a node exists!
- Reply-to: xsl-list at lists dot mulberrytech dot com
thanks for all the info, guys... i am just starting out in XSL and these
were real good tips....
-----Original Message-----
From: Joerg Heinicke [mailto:joerg.heinicke@gmx.de]
Sent: Friday, June 07, 2002 2:36 PM
To: xsl-list@lists.mulberrytech.com
Subject: Re: [xsl] Newbie: See if a node exists!
Anand Kuppa wrote:
> Try using COUNT
> you could do something like
>
> <xsl:when test = "if COUNT(BLOCK) > 0>
> ........what u want to do
> </xsl:when>
>
> lemme know if it worked...
> cheers
Hello Anand,
you never need to count elements, if you only want to know, whether an
element exists or not.
<xsl:if test="BLOCK">
</xsl:if>
is enough.
Even if you want to know whether there are 4 elements or not, you don't need
to count them:
<xsl:if test="BLOCK[4]">
</xsl:if>
tests whether a 4th BLOCK-element does exist.
Your test as above has two little errors:
<xsl:when test="count(BLOCK) > 0">
</xsl:when>
There must not be an 'if' in the test. The element already has the name
<xsl:if/> or <xsl:when/>. And - as David wrote - XML is case sensitive, so
their is no XPATH function COUNT(), but count().
Regards,
Joerg
--
System Development
VIRBUS AG
Fon +49(0)341-979-7419
Fax +49(0)341-979-7409
joerg.heinicke@virbus.de
www.virbus.de
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