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Parsing a List
- From: kenneth dot howlin at laurde dot com
- To: XSL-List at lists dot mulberrytech dot com
- Date: Tue, 21 May 2002 09:23:11 -0700
- Subject: [xsl] Parsing a List
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Guys,
I'm pretty new to XSL and have a problem which I hope you might be able to
help me with.
I have the following code
<!--customer_listStart-->
<xsl:template match="DATALIST">
<table cellpadding="5" cellspacing="0" border="0">
<tr>
<td width="135"><u><font color="green">Company</font></u></td>
<td width="330"><u><font color="green">Address </font></u></td>
<td width="100"><u><font color="green">Phone </font></u></td>
<td width="100"></td>
</tr>
<xsl:apply-templates select="customer"/>
</table>
</xsl:template>
<xsl:template match="customer">
<tr>
<td valign="top"><a><xsl:attribute name="href">
adminViewCompanyByID?companyid=<xsl:value-of select="id"/>&companyname
=<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select="
invoicename"/></a></td>
<td valign="top"><xsl:value-of select="invoiceaddress"/></td>
<td valign="top"><xsl:value-of select="phone"/></td>
</tr>
</xsl:template>
Simply, all this code does is displays all customers contained in the
database. However my problem is that I have 1000s of customers in the
database and as a result all these are returned in one huge list. My web
page is therefore ridicously wrong.
Does anyone know anyway of displaying say 50 Customers at a time with a
'next' and "previous" link to display the next or previous 50.
Any help would be greatly appreciated.
Thanks
- ken
Ken Howlin
Application Developer
LAURDE Limited
Unit 1A
Renmore Business Park
10 Kilcoole Industrial Estate
Kilcoole
County Wicklow
Ireland
mobile: 087 92 85 660
telephone: + 353 1 2878187
email: kenneth.howlin@laurde.com
web: www.laurde.com
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