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large xml document and sorting
- From: Mark Diggory <mdiggory at latte dot harvard dot edu>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Mon, 29 Apr 2002 16:08:29 -0400
- Subject: [xsl] large xml document and sorting
- Reply-to: xsl-list at lists dot mulberrytech dot com
We've got some documents which are upwards of 10 - 20 Mb that we are
have speed issue with in terms of transforming them.
1.) they have about ~800 or so nodes that we need to sort in one portion
of the tree.
2.) they have about 60000 nodes of content in another subtree
ie
<example>
<node-to-be-sorted>...</node-to-be-sorted>
<!-- about 800 of these -->
<node-to-be-sorted>...</node-to-be-sorted>
<rest-of-subtree>
<!-- lots of nodes (~60000) -->
</rest-of-subtree>
</example>
1.) I could care less about the "rest-of-subtree" portion and if I could
get away without parsing it, the better. Is there a "best practice" to
exclude this portion of the tree?
2.) Is there a "best practice" to sort the "node-to-be-sorted" when they
are this many as well? I really need to get this as fast as possible.
Thanks,
-Mark Diggory
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