RE: [xsl] How to pass search path as variable and get back node list.

["Michael Kay" <michael dot h dot kay at ntlworld dot com>]

There is no standard way in XSLT 1.0 of constructing an XPath expression
from a string at run-time. You can do it in several products (e.g. Xalan,
Saxon) using the xx:evaluate() extension function.

Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com

> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of
> Andrew Kerns
> Sent: 27 March 2002 20:46
> To: XSL-List@lists.mulberrytech.com
> Subject: [xsl] How to pass search path as variable and get back node
> list.
>
>
> I have searched FAQ section and can not find answer.
> I know it must be there but I can not find it.
> Please excuse the redundant question.
>
> Can't figure out how to pass search path as variable and get back node
> list.
> I get back search string value instead of node list.
>
> <xsl:param name="DATA_REQUEST_NAME"/>
>
> <xsl:variable name="ftype_search"
> select="concat('//JOB_REQUEST/DATA_REQUEST[@NAME=',$DATA_REQUE
> ST_NAME,']/FILE_TYPE')"/>
> <xsl:variable name="chosen_ftype" select="$ftype_search"/>
>
> xsl:value-of select="$chosen_ftype"/>
>
> Returns
> //JOB_REQUEST/DATA_REQUEST[@NAME=DATAREQUEST4]/FILE_TYPE
>
> How can I get the node list returned instead of the string?
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list