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- From: Matts Isuls <matts dot isuls at AGROLINK dot FI>
- To: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Date: Tue, 19 Mar 2002 11:03:43 +0200
- Subject: [xsl] parent and ..
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi list
How do i get the attribute of a nodes parent? If there are many nodes at the
same leve as the parent i get the first parents attribute.
<?xml version="1.0"?>
<row>
<cell pos="1">
<data>d1</data>
</cell>
<cell pos="2">
<data>d2</data>
</cell>
<cell pos="3">
<data>d3</data>
</cell>
</row>
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" version="1.0" encoding="ISO-8859-1" indent="yes"
omit-xml-declaration="no" standalone="yes"/>
<xsl:template match="/">
<xsl:for-each select="row/cell">
<xsl:value-of select="parent::*/cell/@pos"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Output is '111'. Same result when select="parent::node()/cell/@pos" and
select="../cell/@pos". But how do i get '123'?
matts isuls
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