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Re: Contains(@href. '/') returns false
- From: Jeni Tennison <jeni at jenitennison dot com>
- To: "NILESH PATEL" <jayganesh786 at hotmail dot com>
- Cc: XSL-List at lists dot mulberrytech dot com
- Date: Fri, 8 Mar 2002 12:39:32 +0000
- Subject: Re: [xsl] Contains(@href. '/') returns false
- Organization: Jeni Tennison Consulting Ltd
- References: <F257Qez1enAqpfkNsjU0001ed7b@hotmail.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Nilesh,
You've forgotten some quotes in your call:
> <xsl:call-template name="lastIndexOf">
> <xsl:with-param name="string" select="substring-before(@href, '#')" />
> <xsl:with-param name="char" select="/" />
> </xsl:call-template>
should be:
<xsl:call-template name="lastIndexOf">
<xsl:with-param name="string" select="substring-before(@href, '#')" />
<xsl:with-param name="char" select="'/'" />
</xsl:call-template>
otherwise you're passing the value of the root node as the $char
parameter.
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
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