RE: [xsl] Counting nodes processed

[JAY SCHERER <jay dot scherer at adtran dot com>]

Joerg,

Hmmm... seemed to print out all topics for a category.  Any hints?  Changed it to lt; 1 and it still printed out all topics for a category

Jay

-----Original Message-----
From: Joerg Heinicke [mailto:joerg.heinicke@gmx.de]
Sent: Tuesday, March 05, 2002 1:11 PM
To: xsl-list@lists.mulberrytech.com
Subject: Re: [xsl] Counting nodes processed


<xsl:template match="TopicOwner">
    <xsl:apply-templates select="Category"/>
</xsl:template>

<xsl:template match="Category">
    <xsl:value-of select="@name"/>
    <xsl:apply-templates
select="Topic[count(../preceding-sibling::Category/Topic) &lt; 5]"/>
</xsl:template>

<xsl:template match="Topic">
    <xsl:value-of select="@name"/>
</xsl:template>

Regards,

Joerg

> All,
>
> thanks for the help yesterday.  However, as I was working on this problem
I realized that my xml description was slightly different.  There's a new
twist.  The xml description is now similar to the following:
>
> <Root>
>   <TopicOwner id="1" name="owner1">
>      <Category id ="1" name="Sports">
>         <Topic id="1" name="Basketball"/>
>         <Topic id="2" name="Football"/>
>         <Topic id="3" name="Baseball"/>
>      </Category>
>      <Category id="2" name="FooCategory">
>         <Topic id="4" name="FooTopic"/>
>      </Category>
>   </TopicOwner>
>   <TopicOwner id="2" name="owner2">
>     <Category id="2" name="Entertainment">
>         <Topic id="4" name="Puzzles"/>
>         <Topic id="5" name="Games"/>
>     </Category>
>   </TopicOwner>
> </Root>
>
> Each owner may have > 1 category and each category has > 1 topic.  The
problem is still the same.  I want to retrieve only X number of topics for
each owner.  So, assuming I want to retrieve 4 topics per owner, the output
should be
>
> Owner1
>   Sports
>      Basketball
>      Football
>      Baseball
>   FooCategory
>      FooTopic
>
> Owner2
>   Entertainment
>      Puzzles
>      Games
>
> Thanks,
> jay


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