RE: [xsl] Can I take only parts from node value?

["jp" <jp at tribalstorm dot com>]

Yes, I got it working! 
Thanks for help :)

XML:
<calendar date="200202180800" />

XSL:
<xsl:variable name = "year" select = "substring(@date,0,5)" />
<xsl:variable name = "month" select = "substring(@date,5,2)" />
<xsl:variable name = "day" select = "substring(@date,7,2)" />
<xsl:variable name = "hour" select = "substring(@date,9,2)" />
<xsl:variable name = "minute" select = "substring(@date,11)" />
		
<xsl:value-of select="$year"/>
<xsl:value-of select="$month"/>
<xsl:value-of select="$day"/>
<xsl:value-of select="$hour"/>
<xsl:value-of select="$minute"/>

Regs,
	-JP



-----Original Message-----
From: owner-xsl-list@lists.mulberrytech.com
[mailto:owner-xsl-list@lists.mulberrytech.com] On Behalf Of Michael Kay
Sent: 19. helmikuuta 2002 18:06
To: xsl-list@lists.mulberrytech.com
Subject: RE: [xsl] Can I take only parts from node value?

> If I have XML-tag like this:
> 
> <today date="200202190800" />
> 
> and I want output:
> 
> Time is 08:00
> Date is 19.02 
> Year is 2002
> 
> How can I do this with XSL/T? 

With the substring() function.

Michael Kay
Software AG
home: Michael.H.Kay@ntlworld.com
work: Michael.Kay@softwareag.com 

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