Re: [xsl] determining position of a document included using document function

[Wendell Piez <wapiez at mulberrytech dot com>]

Bryan,

Could you be more specific about what you mean by "the position of 'file' 
in the root document"? The position() function returns the position of the 
current node within the current node list, which is not (at all) the same 
as the position of a node within a document.

<xsl:number> is often a handy way of getting the position of a node in a 
document, or among its siblings, within a hierarchy etc.

Cheers,
Wendell

At 07:42 AM 2/13/02, you wrote:
>If I'm using document() to make a number of simple includes, like
>
><xsl:template match="file">
><xsl:param name="doc" select="document(@href)">
><xsl:for-each select="$doc">
><xsl:apply-templates/>
></xsl:for-each>
>
>is there anyway to find out the position of file in the root document,
>without trying to do <xsl:apply-templates>
><xsl:with-param name="filepos" select="position()"/>
></xsl:apply-templates>
>
>my problem is that I have a template being applied quite low in the included
>documents which needs to know  the position of the including document.


======================================================================
Wendell Piez                            mailto:wapiez@mulberrytech.com
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
   Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list