RE: [xsl] XPATH for attribute with different namespace from element

["Aaron Skonnard" <aarons at develop dot com>]

The following template in doesn't match properly:

	<xsl:template match="rdf:RDF/channel/@rdf:about">
		<xsl:value-of select="current()"/>
	</xsl:template>

...because it identifies channel elements from NO NAMESPACE, not the
default namespace. You need to bind a prefix to the default namespace
and use it in front of channel.

..................................................
Aaron Skonnard, DevelopMentor (aarons@develop.com)
http://www.develop.com  http://www.develop.com/xml
............. http://skonnard.com ................

> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com [mailto:owner-xsl-
> 
> I am trying to make a template match for an rss about attribute but I
> can't seem to get anything to work.
> 
> I tried the following, and all other combinations I could think of
with no
> success.
> rdf:RDF/channel/@rdf:about
> 
> This is my rss file
> <?xml version="1.0" encoding="UTF-8"?>
> <rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#";
> 	xmlns="http://purl.org/rss/1.0";>
> 	<channel rdf:about="newsmlsiteurn">
> 		<title>Various files</title>
> 		<link>http://some.site.com</link>
> 		<description>Various files on some.site</description>
> 	</channel>
> 	<item rdf:about="mayidentifier">
> 		<title>DTD File</title>
> 		<link>dtd\NewsMLv1.0.dtd</link>
> 	</item>
> </rdf:RDF>
> 
> and my stylesheet is.
> 
> <?xml version="1.0"?>
> <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> version="1.0"
> 	xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#";
> 	xmlns="http://purl.org/rss/1.0";>
> 
> 	<xsl:template match="/">
> 		<xsl:apply-templates/>
> 	</xsl:template>
> 
> 	<xsl:template match="rdf:RDF/channel/@rdf:about">
> 		<xsl:value-of select="current()"/>
> 	</xsl:template>
> 
> 	<xsl:template match="text()"/>
> </xsl:transform>
> 
> 



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list