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RE: Simple attribute value replacement question
- From: Jeff Beadle <Jbeadle at manh dot com>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 29 Jan 2002 08:47:43 -0500
- Subject: RE: [xsl] Simple attribute value replacement question
- Reply-to: xsl-list at lists dot mulberrytech dot com
this works:
<?xml version = "1.0" encoding = "UTF-8"?>
<xsl:transform xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"
version = "1.0">
<xsl:template match = "petXML">
<xsl:element name = "animalXML">
<xsl:apply-templates select = "*"/>
</xsl:element>
</xsl:template>
<xsl:template match = "*">
<xsl:copy>
<xsl:copy-of select="attribute::* | text()"/>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="pet[@type='dog']">
<xsl:copy>
<xsl:attribute name="type">canine</xsl:attribute>
<xsl:copy-of select="attribute::*[local-name()!='type'] |
text()"/>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
</xsl:transform>
However, I'd suggest maybe moving your pet/@type conditional logic into one
named template instead of trying to handle all of the permutation with
multiple templates, thereby decentralizing your logic.
perhaps:
<?xml version = "1.0" encoding = "UTF-8"?>
<xsl:transform xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"
version = "1.0">
<xsl:template match = "petXML">
<xsl:element name = "animalXML">
<xsl:apply-templates select = "*"/>
</xsl:element>
</xsl:template>
<xsl:template match = "*">
<xsl:copy>
<xsl:copy-of select="attribute::* | text()"/>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="pet">
<xsl:copy>
<xsl:attribute name="type">
<xsl:call-template name="pet.type">
<xsl:with-param name="type" select="@type"/>
</xsl:call-template>
</xsl:attribute>
<xsl:copy-of select="attribute::*[local-name()!='type'] |
text()"/>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
<xsl:template name="pet.type">
<xsl:param name="type"/>
<xsl:choose>
<xsl:when test="$type='dog'">canine</xsl:when>
<xsl:otherwise><xsl:value-of
select="$type"/></xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:transform>
-Jeff
-----Original Message-----
From: Regina, Paul [mailto:pregina@Engage.com]
Sent: Monday, January 28, 2002 6:40 PM
To: XSL-List@lists.mulberrytech.com
Subject: [xsl] Simple attribute value replacement question
Here is an overly simplified example of what I am trying to do. I want
to convert from one XML to another, I am having trouble changing the
attribute "type". It needs to go from the word "dog" to the word
"canine":
<?xml version="1.0"?>
<petXML>
<pet type="dog">
<color>black</color>
</pet>
</petXML>
To:
<?xml version="1.0"?>
<animalXML>
<pet type="canine">
<color>black</color>
</pet>
</animalXML>
I thought this xsl would do it but apparently not:
<?xml version = "1.0" encoding = "UTF-8"?>
<xsl:transform xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"
version = "1.0">
<xsl:template match = "petXML">
<xsl:element name = "animalXML">
<xsl:apply-templates select = "*"/>
</xsl:element>
</xsl:template>
<xsl:template match = "*">
<xsl:apply-templates select="@type"/>
<xsl:copy-of select = "."/>
</xsl:template>
<xsl:template match="@type[.='dog']">
<xsl:value-of select="canine"/>
</xsl:template>
</xsl:transform>
This is what I get:
<?xml version="1.0"?><animalXML><pet
type="dog"><color>black</color></pet></animalXML>
Can someone please tell me where I am going wrong and how to do this?
Thanks!
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