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Get an element with max. number of certain children element
- From: Xiaocun Xu <xiaocunxu at yahoo dot com>
- To: xsl-list <xsl-list at lists dot mulberrytech dot com>
- Date: Thu, 17 Jan 2002 14:41:37 -0800 (PST)
- Subject: [xsl] Get an element with max. number of certain children element
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
I have researched archive and been using Jeni's
solution on getting the element with max. number of
certain children element via xsl:sort.
<xsl:variable name="maxAttachment">
<xsl:for-each select="LineItem">
<xsl:sort select="count(Attachment)"
order="descending" />
<xsl:if test="position() = 1">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:variable>
Then I wish to use this variable later in:
<xsl:for-each select="$maxAttachment/Attachment">
<xsl:text>,Name,URL,Description</xsl:text>
</xsl:for-each>
The problem seems that xsl:variable will not produce
node-set, which I need. I am aware of the solutions
(via recursion or temp node-set) that uses
$maxAttachment as a number (count(Attachment)), but is
there a more elegent solution that does not require
processor-dependent extensions?
Much thanks,
Xiaocun
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