RE: [xsl] How to add a top level element to the result ?

["Chris Bayes" <chris at bayes dot co dot uk>]

> Interesting.....It worked.

Why? That is how xslt works.

> If I change the expression for match to /A/B//C instead of / 
> ie,similar to the match expression in the next rule then it 
> wont work. Why is it so?

But it will. Try this. But it won't give you the output you want.

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/A/B//C">
	<Message>
		<xsl:element name="{@attr1}">
			<xsl:apply-templates />
			<xsl:value-of select="@attr2"/>
		 </xsl:element>
	 </Message>
</xsl:template>
<xsl:template match="T"/>
</xsl:stylesheet>

Ciao Chris

XML/XSL Portal
http://www.bayes.co.uk/xml


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