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Re: Correct syntax for removing duplicates from sorted list

Hi Chris,

Thanks for the help. I have the doug tidwell xslt book and am
basicaly trying to go through it. But it doesnt have exactly what
I need and I'm taking ideas from here and there to slot into
my gobbldygook and you know the rest! By the way I have
xml writer to test the syntax just my crap programming mind
and the strangness of xslt syntax is confusing!

Anyway.umm it still doesnt remove the duplicate values, heres my output with
your new version (much more elegant than my nightmare of confusion!)
I was a poet and I didnt know it!

1. 23220
2. 23470
3. 23470
4. 23470
5. 23470
6. 23470
7. 23470
8. 83470
9. 212120
10. 223232
11. 231212
12. 2346456
13. 27675340

cheers
A.
-----Original Message-----
From: Chris Bayes <chris@Bayes.co.uk>
To: xsl-list@lists.mulberrytech.com <xsl-list@lists.mulberrytech.com>
Date: Monday, December 17, 2001 2:31 PM
Subject: RE: [xsl] Correct syntax for removing duplicates from sorted list


>>  <xsl:if test=not".=last">
>What is this gobbledygook??????
>What processor are you using that you can get ANY result????
>Why not just do
><xsl:template match ="/">
> <html>
>    <body>
> <xsl:for-each select="LOG/DIRECT/TARGET_CHARACTER_ID[. !=
>preceding::TARGET_CHARACTER_ID]">
> <xsl:sort select="." data-type="number"
>order="ascending" />
> <xsl:value-of select="position()" />. <xsl:value-of
>select="." />
> </xsl:for-each>
>    </body>
> </html>
></xsl:template>
>
>Ciao Chris
>
>XML/XSL Portal
>http://www.bayes.co.uk/xml
>
>
>> -----Original Message-----
>> From: owner-xsl-list@lists.mulberrytech.com
>> [mailto:owner-xsl-list@lists.mulberrytech.com] On Behalf Of
>> Ahmad J Reeves
>> Sent: 17 December 2001 13:00
>> To: xsl-list@lists.mulberrytech.com
>> Subject: [xsl] Correct syntax for removing duplicates from sorted list
>>
>>
>> Hi,
>>
>> I am trying to remove duplicate copies of context nodes from
>> a sorted list. My xml doc looks like this:-
>>
>> <LOG>
>>       <DIRECT>
>>       <COMMUNICATION_TYPE> PAGETELL </COMMUNICATION_TYPE>
>>       <Invoc_serial> 27 </Invoc_serial>
>>       <Serial> 3087908 </Serial>
>>       <USAGE> TELL </USAGE>
>>       <MESSAGE_TYPE> EMOTE </MESSAGE_TYPE>
>>       <CHARACTER_ID> 44639 </CHARACTER_ID>
>>       <CHARACTER_STATUS> 3 </CHARACTER_STATUS>
>>       <LOCATION_ID> 45040 </LOCATION_ID>
>>       <TARGET_CHARACTER_ID> 2346456 </TARGET_CHARACTER_ID>
>>       <TARGET_CHARACTER_STATUS> 6 </TARGET_CHARACTER_STATUS>
>>       <TARGET_CHARACTER_LOCATION_ID> 23222
>> </TARGET_CHARACTER_LOCATION_ID>
>>       <MESSAGE>hello</MESSAGE>
>>       <TIME> 'Mon, 26 Nov 2001 15:40:29 +0000' </TIME>
>>       </DIRECT>
>>
>>  *then a few hundred more like that*
>>
>> </LOG>
>>
>> My xml stylesheet as is looks like this:-
>>
>>
>> <xsl:stylesheet
>>         xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>>         version="1.0">
>>  <xsl:output method="html"/>
>>
>>  <xsl:variable name="last">
>>  </xsl:variable>
>>
>>  <xsl:template match ="/">
>>  <xsl:for-each select="LOG/DIRECT/TARGET_CHARACTER_ID">
>>  <xsl:variable name="last" select="LOG/DIRECT/TARGET_CHARACTER_ID"/>
>>  <xsl:sort select="." data-type="number"/>
>>  <xsl:value-of select="position()"/>
>>  <xsl:text>. </xsl:text>
>>
>>   <html>
>>     <body>
>>      <xsl:if test=not".=last">
>>           <xsl:value-of select="."/><br></br>
>>         </xsl:if>
>>     </body>
>>   </html>
>>   </xsl:for-each>
>>  </xsl:template>
>> </xsl:stylesheet>
>>
>> And my sorted but duplicated output is something like this:-
>>
>> 1. 23220
>> 2. 23470
>> 3. 23470
>> 4. 23470
>> 5. 23470
>> 6. 23470
>> 7. 23470
>> 8. 83470
>> 9. 212120
>> 10. 223232
>> 11. 231212
>> 12. 2346456
>> 13. 27675340
>>
>> So every time I get to the context node(in this case
>> "TARGET_CHARACTER_ID") I need to check if it matches the
>> previous one and if so NOT to output it. This should give me
>> a unique list rather than a total occurences count. The code
>> as is (oops!) just tests to see if it equals itself I think!
>> and I've been looking at axis but as I am comparing .=. then
>> I'm not sure the best way to proceed, as I need to test with
>> the previous 'iteration' as it were.
>>
>> Any help gratefully received!
>>
>> Cheers
>>
>> Ahmad (p.s cheers Jen and Chris for your previous help)
>>
>>
>>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>>
>>
>
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
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