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RE: ordering and iteration problem


Hello Jeni!

> Yes - there's no other way of testing for node identity unless there's
> something about the node that gives it an identity (such as an ID
> attribute). 

Except for forcing the processor to check identity on its own by count(x | y) = 1 idiom, if I'm not mistaking...

---
Oleg Tkachenko,
Multiconn International, Israel 


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