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Re: using xsl to check for duplicate elements
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: Re: [xsl] using xsl to check for duplicate elements
- From: Jörg Heinicke <joerg dot heinicke at gmx dot de>
- Date: Wed, 24 Oct 2001 00:45:51 +0200
- References: <0E10BFCC43DED311B8A900D0B7260265EFEED8@exch1.globeop.com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
One method is to test on preceding(-sibling) or following(-sibling) nodes:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:template match="Instruments|Equity">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:if test="not(preceding-sibling::*[name()=name(current()) and
text()=current()/text()])">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Another method is to use keys for grouping with Muenchian Method:
http://www.jenitennison.com/xslt/grouping/muenchian.xml.
Joerg
----- Original Message -----
From: "Pankaj Jain" <pjain@globeop.com>
To: "XSL List (E-mail)" <xsl-list@lists.mulberrytech.com>
Sent: Wednesday, October 24, 2001 12:19 AM
Subject: [xsl] using xsl to check for duplicate elements
> Hi all,
> Is there a way to check an XML file for duplicate elements and eliminate
the
> second one? i.e. If I have the following XML:
>
>
> <?xml version="1.0" standalone="yes">
> <Instruments>
> <Equity>
> <ISSUE_ID>108558</ISSUE_ID>
> <RIC>IBM.N</RIC>
> <CTRY_ID>648</CTRY_ID>
> <EXCH_ID>224</EXCH_ID>
> <NAME>IBM</NAME>
> <EXCH_ID>224</EXCH_ID>
> <ISSUE_ID>108558</ISSUE_ID>
> <CTRY_ID>648</CTRY_ID>
> </Equity>
> </Instruments>
>
>
> What would I do in XSL to create a new XML file that looks like the
> following:
>
> <?xml version="1.0" standalone="yes">
> <Instruments>
> <Equity>
> <ISSUE_ID>108558</ISSUE_ID>
> <RIC>IBM.N</RIC>
> <CTRY_ID>648</CTRY_ID>
> <EXCH_ID>224</EXCH_ID>
> <NAME>IBM</NAME>
> </Equity>
> </Instruments>
>
> Thanks
> Pankaj
>
> -----
> Pankaj Jain
>
>
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