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Re: questions.
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] questions.
- From: Jörg Heinicke <joerg dot heinicke at gmx dot de>
- Date: Thu, 04 Oct 2001 15:39:33 +0200
- References: <NFBBJMOMJMKAFOBEPAMNMEJOCDAA.mihirg@geometricsoftware.com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi Mihir,
I think here you have a problem of unserstanding XSL. You don't modify the
original XML-tree, you create a new one. This is important!! If you really
want to "translate" <b> to <x>, you don't need to "delete" <b>, you only
need to add <x>.
An example stylesheet:
<xsl:template match="a|c">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="b">
<x>
<xsl:apply-templates/>
<m></m>
<n></n>
</x>
</xsl:template>
Hope this helps,
Joerg
Mihir D. Gore wrote:
> but if want to replace node b with node z ie
>
> <a>
> <b>
> <c></c>
> </b>
> </a>
>
> is changed to
> <a>
> <x>
> <c></c>
> <m></m>
> <n></n>
> <x>
> </a>
>
> I can achive this by simply deleting node b and its chilren and adding node
> x.
> Is there any other way around this?
>
> mihir
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Manu KY
> Sent: Thursday, October 04, 2001 2:09 PM
> To: xsl-list@lists.mulberrytech.com
> Subject: Re: [xsl] questions.
>
>
> Hi,
> write xsl:template match = "b"
>
> Manu
>
>>hi,
>>I have a xml file in the form
>>
>><a>
>> <b>
>> <c></c>
>> </b>
>></a>
>>
>>I want to add two more children to node b say m and n so that the
>>
> resultant
>
>>xml looks like this.....
>>
>><a>
>> <b>
>> <c></c>
>> <m></m>
>> <n></n>
>> </b>
>></a>
>>
>>BUT in the xsl file in want to specify the path with respect to node b.
>>How do i do it?
>>mihir
--
System Development
VIRBUS AG
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