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Re: getting XSL to output XSL...
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] getting XSL to output XSL...
- From: Gary Frederick <gary dot frederick at jsoft dot com>
- Date: Thu, 16 Aug 2001 06:21:41 -0500
- Organization: Jefferson Software
- References: <20010816155306.A25869@team.ph.inter.net>
- Reply-To: xsl-list at lists dot mulberrytech dot com
I wrote a stylesheet that outputs another stylesheet. Here is a snippet
...
<xsl:element name="xsl:stylesheet">
<xsl:attribute name="version">1.0</xsl:attribute>
...all the content...
</xsl:element>
...
It should output this
<xsl:stylesheet version="1.0">
...all the content...
</xsl:stylesheet>
There are several other ways to get the xsl tags out. The above uses
xsl:element which is perhaps a bit 'wordy' but was easier for me to
understand when I was first learning.
Gary
Rafael 'Dido' Sevilla wrote:
> How do I write a stylesheet that generates another stylesheet? Will
> XSLT processors be smart enough to note that:
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:xslout="http://www.w3.org/1999/XSL/Transform"
> version="1.0"/>
>
> the <xslout:.../> tags are not supposed to be processed? I've thought
> of slightly modifying the namespace URI for the new stylesheet but I
> want to avoid making manual changes to the result if at all possible.
>
> This is probably in the FAQ somewhere, I know, but i can't seem to
> find any topic that seems suitable...
>
>
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