Re: [xsl]xpath for getting file version

["Antony Suryadinata" <antodinata at bigfoot dot com>]

Re: [xsl]xpath for getting file versionThank you Jeni for the suggestions and Dimitre for the generic template.

Jeni wrote:
> Second, you could have a two-stage process (either with two 
> stylesheets or using a node-set() extension function to do it all in 
> one stylesheet). In the first pass, construct XML like the above, with 
> a date attribute giving the entire date, and then use the XPath above 
> in the key.

If I use the second suggestion using the node-set() extension function, how would I use the <xsl:key>?
Say if I put my modified XML into a variable called "temp".

<xsl:variable name="modified" select="xalan:nodeset($temp)"/>
<xsl:key name="maxfile" match="$modified/person" use="versions/version[not(@date &lt; ../version/@date)]/@name"/>

Is that how?

Thank you for your help,

Antony



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