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Re: compare two lists of values question
- To: Hal at solspark dot com
- Subject: [xsl] Re: compare two lists of values question
- From: Dimitre Novatchev <dnovatchev at yahoo dot com>
- Date: Tue, 7 Aug 2001 21:09:27 -0700 (PDT)
- Cc: xsl-list at lists dot mulberrytech dot com
- Reply-To: xsl-list at lists dot mulberrytech dot com
Friedlander, Hal wrote:
> I need to compare two lists of values and display the value of any name
> element not in both lists.
> The xml is like this:
> <Merchants>
> <USMerchants>
> <name>store1</name>
> <name>store2</name>
> <name>store3</name>
> <name>store4</name>
> <name>store5</name>
> <name>store6</name>
> </USMerchants>
> <UKMerchant>
> <name>store1</name>
> <name>store2</name>
> <name>store3</name>
> <name>store4</name>
> <name>store5</name>
> <name>store99</name>
> </UKMerchant>
> </Merchants>
Hi Hal,
Assumng that a name cannot appear more than once in a list (which seems to be your
case), then a simple way to achieve the desired result is as follows:
<xsl:key name="kName" match="name" use="."/>
Using the above xsl:key, the following XPath expression returns a node-set of all
names that appear only once (and therefore only in one of the lists).
/Merchants/*/name[count(key('kName', .)) = 1]
Hope this helped.
Cheers,
Dimitre Novatchev.
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