Re: [xsl] change a list of attribute name

[Xiaocun Xu <xiaocunxu at yahoo dot com>]

Hi, Jeni:

That's a great and straight-forward idea.  Unfortunely
my problem is a little more complicated than that :(

I failed to show the more complicated case where
"Organization Unique ID" need to be transformed into
"OrganizationCode".  There isn't a set rule to
transform from one to another.  So I am looking for a
more general solution where one set of values can be
mapped to another set.

Much thanks,
Xiaocun

--- Jeni Tennison <mail@jenitennison.com> wrote:
> Hi Xiaocun,
> 
> > I have a header which consisted of normal names
> such as "Last Name".
> > For each of these, I would like to replace it with
> a valid XML
> > attribute name such as LastName. What would be the
> best way to do
> > it?
> 
> Remember that the name attribute of xsl:attribute
> can hold an
> attribute value template, so you can compute the
> value for the
> attribute name dynamically and use that. For
> example, if you only need
> to get rid of spaces, then using translate() would
> probably be your
> best bet:
> 
>   <xsl:for-each select="$header/cell">
>     <xsl:attribute name="{translate(., ' ', '')}">
>        ...
>     </xsl:attribute>
>   </xsl:for-each>
> 
> If you can compute the names that you need to
> populate a node set,
> then you can compute them directly within the
> xsl:for-each, so I don't
> think that you will have to use an intermediate node
> set at all.
> 
> I hope that helps,
> 
> Jeni
> 
> ---
> Jeni Tennison
> http://www.jenitennison.com/
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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