[xsl] Q on copying

[Rosa I-Ting Cheng <Rosa at ceanet dot com dot au>]

Can anyone please tell me how to copy XML into certain sorted order while
keeping the attributes of the root element as is?
ie the following is my XML

<Root att1="" att2="">
<Info sort="2"/>
<Info sort="5"/>
<info sort="1"/>
<other sort="3"/>
<other sort="5"/>
<other sort="2"/>
</Root>

I want to turn that XML into
<Root att1="" att2="">
<info sort="1"/>
<Info sort="2"/>
<Info sort="5"/>
<other sort="3"/>
<other sort="4"/>
<other sort="5"/>
</Root>

This is what I have so far..
<xsl:template name="Root">
<Root>
<xsl:for-each select="info">
	<xsl:sort select="sort"/>
	<xsl:copy-of select="."/>
</xsl:for-each>
<xsl:for-each select="other">
	<xsl:sort select="sort"/>
	<xsl:copy-of select="."/>
</xsl:for-each>
</Root>
</xsl:template>

Thanx!

Rosa




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