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Re: copying child nodes n-level deep
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] copying child nodes n-level deep
- From: Oliver Becker <obecker at informatik dot hu-berlin dot de>
- Date: Thu, 26 Jul 2001 16:58:45 +0200 (MET DST)
- Reply-To: xsl-list at lists dot mulberrytech dot com
What about
<xsl:template match="B">
<xsl:copy-of select="*/*" />
</xsl:template>
Cheers,
Oliver
You wrote:
> Given:
> <A>
> <B>
> <C id="1">
> <D id1="2">
> <E>hello</E>
> </D>
> </C>
> </B>
> </A>
>
> I would like to copy all the elements and their children starting from D.
> The logic is, take the grand-child of B (in this case D) and copy it (along
> with all its children). The only known element name is B..How can I write a
> generic xsl code such that from the following schema:
>
> <AA>
> <B>
> <CC id="1">
> <DD id1="2">
> <EE>hello</EE>
> <FF>hello2</FF>
> </DD>
> </CC>
> </B>
> </AA>
>
> I can copy (B's grand child (DD) and its children):
> <DD id1="2">
> <EE>hello</EE>
> <FF>hello2</FF>
> </DD>
>
> Thanks a lot for the help.
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