RE: [xsl] Position of a result tree fragment

["Michael Kay" <mhkay at iclway dot co dot uk>]

A result tree fragment does not have a parent.

Mike Kay
Software AG

> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Laurence O
> Garfield
> Sent: 19 July 2001 00:08
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] Position of a result tree fragment
> 
> 
> If I am passing a result tree fragment from one template to 
> another using
> a variable, is there any way to determine what the fragment's position
> within its parent was originally?  According to the XSLT spec 
> I can't use
> /, //, or [] on result tree fragments, so I can't use 
> [position()].  Is
> there some other way, or do I have to pass the position of the node
> through as a second variable as well?
> 
> --Larry Garfield
> lgarfiel@students.depaul.edu
> 
> DePaul Linux Users Group Secretary
> 
> -- "If at first you don't succeed, skydiving isn't for you." :-)
> 
> 
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