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RE: Conditional variable assignment with node-set as value
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] Conditional variable assignment with node-set as value
- From: "Michael Kay" <mhkay at iclway dot co dot uk>
- Date: Wed, 18 Jul 2001 02:37:54 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
> I uses Saxon6.0.2 as XSLT processor.
Upgrade! The current version is 6.4.3.
> I currently have a need to use conditional variable
> assignment with node-set as value. I tried to use
> saxon:node-set, but still gets the error:
I suspect the error is from the way you are using this variable, not from
the way you are setting it up. Within this xsl:variable, the two calls on
saxon:node-set() seem to be unnecessary: it's never necessary to call
saxon:node-set on something that is already a node-set, which both these
expressions are.
I'm afraid I don't know quite what you mean by conditional variable
assigment. Have you considered the syntax:
<xsl:variable name="v" select="$ns1[$condition] | $ns2[not($condition)]"/>
Mike Kay
Software AG
> At XSLT 1.0, conversion of a result tree fragment to a
> node-set is not allowed.
> My XSLT code looks like:
> <xsl:variable name="extended-attrs-bid">
> <xsl:choose>
> <xsl:when
> test="normalize-space(RFQDomainAttributeDefinition)">
> <xsl:value-of
> select="saxon:node-set(RFQDomainAttributeDefinition[@Domain
> = 'lbid']/ExtendedAttributeDefinition)" />
> </xsl:when>
> <xsl:otherwise>
> <xsl:value-of
> select="saxon:node-set(Bid/ExtendedAttribute[generate-id()
> = generate-id(key('extended-attrs-bid-index',
> @ExtendedAttributeCode))])" />
> </xsl:otherwise>
> </xsl:choose>
> </xsl:variable>
> How to conditionally assign the node-set value I
> needed?
>
> Much thanks,
> Xiaocun
>
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