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Re: Question about xsl-xslt


On Tuesday 22 May 2001 20:29, Dennis wrote:
> The problem is in the defination of
>      <xsl:variable name="level" select="3"></xsl:variable>
> When u define the select="3" its looking for a element node  3.
> Rather if u want to store a value u need to declare it as --> select="'3'"

That's not right.
An expression "3" will always be recognized as a number, because a qualified
node name has to start with a letter or underscore.

I
-- 
Ingo Schildmann                                                ingoschi@web.de

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