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Re:recursive problem with full path and position info
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] Re:recursive problem with full path and position info
- From: "Yang" <sfyang at unisvr dot net dot tw>
- Date: Mon, 30 Apr 2001 15:06:55 +0800
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi,
Dan, I found I got a different solution from yours while experimenting Jeni
method as you suggested.
I have root(2) instead of root(1) , perhaps you can correct me the missing
point.
I am using Msxml3, and ie5, the complete xsl are listing below fyi.
Thanks,
Sun-fu Yang
sfyang@unisvr.net.tw
** output result **
root(2).a(1).b(1) = '1'
root(2).a(1).b(2) = '2'
root(2).a(2).b(1) = '3'
root(2).a(2).b(2) = '4'
**xsl file **
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="*">
<xsl:param name="path" />
<xsl:apply-templates select="*">
<xsl:with-param name="path" select="concat($path, name(), '(',
position(), ').')" />
</xsl:apply-templates>
</xsl:template>
<xsl:template match="*[not(*)]">
<xsl:param name="path" />
<xsl:value-of select="$path" />
<xsl:value-of select="name()" />(<xsl:value-of select="position()" />
<xsl:text>) = '</xsl:text>
<xsl:value-of select="." />'
<xsl:text />
</xsl:template>
</xsl:stylesheet>
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