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Re: union/intersection on attribute values
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] union/intersection on attribute values
- From: Dan Diebolt <dandiebolt at yahoo dot com>
- Date: Sat, 21 Apr 2001 07:18:53 -0700 (PDT)
- Reply-To: xsl-list at lists dot mulberrytech dot com
>select="item/@set1[. = /items/item/@set2]"
>select="item/@set1[not(. = /items/item/@set2)]"
>select="item/@set2[not(. = /items/item/@set1)]"
>
>that'll return duplicate entries which can be removed eg by using the
>count(.| trick I used on a posting early today (and it's too late to
>reconstruct:-)
David: Could you provide a version using your count() method to kill
the duplicates? I would like to compare it to the enclosed method
I adapted using your select expressions. I am especially interested
in how you define the keys and how many are needed using count().
Regards,
Dan
**********
XSLT Fragment:
<xsl:template match="items">
<xsl:variable name="in1and2" select="item/@set1[. = /items/item/@set2]"/>
<xsl:for-each select="$in1and2[generate-id(..)=generate-id(key('x1',.))]">
in1and2=<xsl:value-of select="."/><br/>
</xsl:for-each>
<hr/>
<xsl:variable name="in1not2" select="item/@set1[not(. = /items/item/@set2)]"/>
<xsl:for-each select="$in1not2[generate-id(..)=generate-id(key('x1',.))]">
in1not2=<xsl:value-of select="."/><br/>
</xsl:for-each>
<hr/>
<xsl:variable name="in2not1" select="item/@set2[not(. = /items/item/@set1)]"/>
<xsl:for-each select="$in2not1[generate-id(..)=generate-id(key('x2',.))]">
in2not1=<xsl:value-of select="."/><br/>
</xsl:for-each>
</xsl:template>
XML Fragment:
<items>
<item id="1" set1="A"/>
<item id="2" set1="B"/>
<item id="3" set1="C"/>
<item id="4" set2="A"/>
<item id="5" set2="C"/>
<item id="6" set2="D"/>
<item id="7" set2="D"/>
<item id="8" set2="D"/>
<item id="9" set2="E"/>
<item id="a" set2="E"/>
<item id="b" set2="F"/>
</items>
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