This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
Re: Starting loop at another node
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Starting loop at another node
- From: Wendell Piez <wapiez at mulberrytech dot com>
- Date: Tue, 17 Apr 2001 12:28:29 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
Tanz:
At 04:33 PM 4/17/01, you wrote:
>I am trying to start the loop at node 4 (child 4) of the 'whatever' parent:
><Whatever> <child1>
> <child2>
> <child3>
> <child4>
> <child5>
> <child6>
> ....
></Whatever>
>
>I am using the following
>
> <xsl:for-each select="Whatever">
> <xsl:choose>
> <xsl:when test="position()>3"> <!-- Here is the problem -->
> <xsl:for-each select="*[text()]"> <!--start of process-->
> <h3><font color="#00007f"><i><xsl:value-of
>select="name()"/></i></font></h3>
> <p><font color="#008000"><xsl:value-of select="."/></font></p>
> </xsl:for-each> <!--end of process-->
> </xsl:when>
> </xsl:choose>
> </xsl:for-each>
>
>At the moment the display is not doing as I wish.
<xsl:for-each select="Whatever/child[position() > 3]"> is more succinct
and would get you the nodes you want. No inner choose/when or for-each is
necessary.
Your problem is happening because your xsl:when is evaluating the position
of the Whatever node, not its children.
Regards,
Wendell
>Thanks.
>
>Tanz
>
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
======================================================================
Wendell Piez mailto:wapiez@mulberrytech.com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
----------------------------------------------------------------------
Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list