RE: [xsl] Using position() with sorted node

["Michael Kay" <mhkay at iclway dot co dot uk>]

> position() does return the position of the current node in
> the current node
> list (which is created using an <xsl:apply-templates> or
> <xsl:for-each> with
> or without any <xsl:sort> elements.) Unfortunately, sorting
> the node list
> makes accessing the preceding nodes rather tricky since the
> preceding and
> preceding-sibling axes work on the document and not the
> sorted node list.

I think the only way of accessing the preceding node in sorted order is to
create a sorted copy of the original data and then process this using the
node-set() extension function. Either that, or find a different solution to
the requirement.

Mike Kay
Software AG


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