Re: [xsl] Node set

[Jeni Tennison <mail at jenitennison dot com>]

Hi Yue,

> If I have the order in XML  file like:
> title1,title2,title3,title4,title5
>
> The order we should display MAY be:
> title1,title3,title2(on the left column)
> title5,title4(on the right column)
> again, any title element may not be in the XML file, means if I don't find
> title3, I should display:
> title1,title2(on the left column)
> title5,title4(on the right column)

From this description, you could use:

  <table>
     <xsl:variable name="top-row"
                   select="count(title1 | title2 | title3)" />
     <xsl:variable name="bottom-row"
                   select="count(title4 | title5)" />
     <xsl:if test="$top-row">
        <tr>
           <xsl:apply-templates select="title1" />
           <xsl:apply-templates select="title3" />
           <xsl:apply-templates select="title2" />
           <xsl:if test="$bottom-row &gt; $top-row">
              <td />
           </xsl:if>
        </tr>
     </xsl:if>
     <xsl:if test="title4 or title5">
        <tr>
           <xsl:apply-templates select="title5" />
           <xsl:apply-templates select="title4" />
           <xsl:if test="$top-row &gt; $bottom-row">
              <td />
              <xsl:if test="$top-row - $bottom-row = 2">
                 <td />
              </xsl:if>
           </xsl:if>
        </tr>
     </xsl:if>
  </table>

With the following template giving the cells for each title (it will
only be processed if there *is* such a title):
  
<xsl:template match="title1 | title2 | title3 | title4 | title5">
   <td><xsl:value-of select="." /></td>
</xsl:template>

Of course, you may not have covered all possible scenarios in your
description.

I hope that helps,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/



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