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Re: xsl to echo input xml
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] xsl to echo input xml
- From: Mike Brown <mike at skew dot org>
- Date: Wed, 24 Jan 2001 15:27:41 -0700 (MST)
- Reply-To: xsl-list at lists dot mulberrytech dot com
_ryan wrote:
> If I want to pass an xml to an xsl, and then have the xsl simply repeat
> what's in the xml, how would I go about that?
What you want is called an "identity transformation" and it is explained
in the XSLT spec in section 7.5, at http://www.w3.org/TR/xslt#copying
The template is
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
The reason why your template won't work should be self-evident after
reading sections 5.1, 5.4, and 5.8:
http://www.w3.org/TR/xslt#section-Processing-Model
http://www.w3.org/TR/xslt#section-Applying-Template-Rules
http://www.w3.org/TR/xslt#built-in-rule
Note that XSLT only has access to the logical contents of the XML document
as reported by a parser, so 'physical' structures like entity references
and attribute order may not be preserved in your output.
- Mike
____________________________________________________________________
Mike J. Brown, software engineer at My XML/XSL resources:
webb.net in Denver, Colorado, USA http://skew.org/xml/
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