Re: [xsl] problem with Passing Parameters to Templates

["helen li" <helen_p_li at hotmail dot com>]

I also want to call the named templates with any decendent elements of the 
current node, for example, './/codec'.

Thanks - Helen

>From: "helen li" <helen_p_li@hotmail.com>
>Reply-To: xsl-list@lists.mulberrytech.com
>To: xsl-list@lists.mulberrytech.com
>Subject: Re: [xsl] problem with Passing Parameters to Templates
>Date: Mon, 22 Jan 2001 11:05:26 -0500
>
>Thanks, David.
>
>OK, my question simply is: Can I output the value of a element which is
>passed thru parameter ( in my case the element is 'codec' and its value is
>1234 )? I understand that I can do something simply like <xsl:value-of
>select="codec">. But I would like to do it with named template so that I 
>can
>call the template for other elements.
>
>in XML file, there are two lines like
><codec>1234</codec>
><desc>5678</desc>
>
>And the xsl file will be something like:
>
>     <xsl:call-template name="opt_template">
>         <xsl:with-param name="node"  select="'codec'"/>
>     </xsl:call-template>
>
>     <xsl:call-template name="opt_template">
>         <xsl:with-param name="node"  select="'desc'"/>
>     </xsl:call-template>
>
>     <xsl:template name="opt_template">
>        <xsl:param name="node"></xsl:param>
>
>=======what should be in here to output the value of element codec or
>desc????
>
>     </xsl:template>
>
>Is it doable?
>
>Thanks,
>
>Helen
>
>>From: David Carlisle <davidc@nag.co.uk>
>>Reply-To: xsl-list@lists.mulberrytech.com
>>To: xsl-list@lists.mulberrytech.com
>>Subject: Re: [xsl] problem with Passing Parameters to Templates
>>Date: Mon, 22 Jan 2001 15:25:33 GMT
>>
>> > Did I do something wrong?
>>
>>yes:-)
>>
>>Firstly the simple answer to your question:
>>
>> > What I really want to do is to output the value of element codec(
>>
>>appears to be
>>
>><xsl:value-of select=".//codec"/>
>>
>>in which case you don't have any params to worry about, but
>>to see what's wrong with your code node that you have defined $node
>>to be a string. It is always the empty string or 'codec'.
>>
>>           <xsl:if test=".//*[$node]">
>>
>>this is using $node in a predicate so the string will be coerced to a
>>boolean. If it is empty (ie if the named template is called without an
>>explicit parameter) then it will have boolean value false
>>
>>*[false()]
>>
>>selects all elements for which false is true.
>>
>>.// searches for all descendents of the current node for which the above
>>is true.
>>
>>As false is never true this will return the empty nosde set.
>>
>>This node set is used in an if test so will be coerced to boolean as
>>false. So in this case the value-of clause will be skipped.
>>
>>If $node is codec then [$codec] is the same as [true()] so
>>.//*[$codec]
>>will be true if the current node has any element children and will be
>>false otherwise.
>>
>>If it is true then the value-of will be evaluated. which will return the
>>value of the first codec descendent.
>>
>>As you see the xsl:if isn't doing anything useful in either case
>>you could just miss it out and say
>>        <xsl:value-of select=".//*[name()=$node]"/>
>>
>>If there are no elements of that name, you don't need to test with
>>xsl:if, you just get nothing returned.
>>
>>David
>>
>>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>>
>
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