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Re: Re: Namespace questions
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Re: Namespace questions
- From: Ayelet Kotzer <akotzer at savvion dot com>
- Date: Tue, 02 Jan 2001 11:38:56 -0800
- Organization: Savvion
- References: <20001230072255.3316.qmail@web6305.mail.yahoo.com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi Dimitri,
Can you give me an example. I am not sure where is each of the commands
that you mention.
For example the line
xmlns:m="B" exclude-result-prefixes="m" . Where should it appear ?
Thanks,
Ayelet
Dimitre Novatchev wrote:
> Ayelet,
>
> You can get rid of the namespace declaration on the child nodes by
> adding the following to your xsl:stylesheet element:
>
> xmlns:m="B" exclude-result-prefixes="m"
>
> Then you'll get in your output:
>
> <A1>something </A1><A2 att="att1">something </A2>
>
> However, the top element(s) that declare the namespace will still be
> copied with the namespace declaration. So, the result of processing
> your fragment will look like this:
>
> <m:A xmlns:m="B"><A1>something </A1><A2 att="att1">something
> </A2></m:A>
>
> Obviously, you must have a separate template that matches all
> m:yourNames elements you'd like to copy without the namespace
> declaration on them. Then in this template use xsl:element and
> xsl:attribute and specify the local-name().
>
> Dimitre.
>
> Ayelet Kotzer wrote:
>
> (Desired) Output:
> <A >
> <A1>something </A1>
> <A2 att="att1>something </A2>
> </A>
>
> What I got is something like this:
> <A1 xmlns:m="B">something </A1>
> <A2 xmlns:m="B" att="att1 >something </A2>
>
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