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sum() of nodeset
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: sum() of nodeset
- From: Shimon Pozin <shimonp at servicesoft dot com>
- Date: Thu, 30 Nov 2000 11:32:12 -0500
- Reply-To: xsl-list at mulberrytech dot com
Hello!
I have xml file like this:
----------xml-------------
<xml>
<row m=1 y=1999 v=3 />
<row m=1 y=2000 v=43 />
<row m=2 y=1999 v=6 />
<row m=2 y=2000 v=56 />
...
</xml>
--------------------------
and xsl like this (only relevant part is quoted to save space):
-------------xsl----------
<xsl:for-each select="//row[@m=1]">
<tr>
<td><xsl:value-of select="@m" /></td>
<td><xsl:value-of select="@y" /></td>
<td><xsl:value-of select="@v" /></td>
</tr>
</xsl:for-each>
--------------------------
Now, I am trying to get sum of values for a particular m (stands for month,
of course). I tried:
<td><xsl:value-of select="@m[@m=1]" /></td>, but get 0 in this case
If I try:
<td><xsl:value-of select="//@m[@m=1]" /></td> I get sum of _all_ rows
rather than sum of v's for a particular month. Is there a simple
solution to my problem without transforming the original file to
some intermediate format?
Thanks a lot for any ideas,
Shimon
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