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RE: question with using Muenchian/xsl:key (Re: sort/group/count probl em)
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: RE: question with using Muenchian/xsl:key (Re: sort/group/count probl em)
- From: Xiaocun Xu <XXu at CommercialWare dot com>
- Date: Wed, 15 Nov 2000 14:24:42 -0500
- Reply-To: xsl-list at mulberrytech dot com
Thanks for the tip, you are making a very good point, I will sure add it to
my code.
Thanks again,
Xiaocun Xu
xxu@commercialware.com
> -----Original Message-----
> From: G. Ken Holman [mailto:gkholman@CraneSoftwrights.com]
> Sent: Wednesday, November 15, 2000 5:27 AM
> To: xsl-list@mulberrytech.com
> Subject: Re: question with using Muenchian/xsl:key (Re:
> sort/group/count
> probl em)
>
>
> At 00/11/11 23:30 +0000, David Carlisle wrote:
> > >
> > > key('items-by-itemid', @itemid) returns all items with
> the same @itemid in
> > > the entire XML document. I just want all items with the
> same @itemid in
> > > each of the itemlist element, how can I do that?
> >
> >don't you just want to replace
> >
> ><xsl:key name="items-by-itemid" match="item" use="@itemid"/>
> >
> >by something like
> >
> ><xsl:key name="items-by-itemid" match="item"
> >use="concat(generate-id(..),@itemid)"
> >/>
> >
> >so that your key values are all specific to a given itemlist.
> >
> >Not that I've tried it....
>
> This is precisely the basis of a section of my instructor-led
> tutorial and
> exercise to do sub-tree subsetting of the xsl:key facility,
> but with one
> addition.
>
> I teach use="concat(generate-id(subtree-root-expression),'
> ',value-expression)" because of the remote (but possible)
> synthesis of
> ambiguous use values. If the generated id of two nodes were "N1" and
> "N12", and the corresponding value expressions were
> coincidentally "23" and
> "3", then the values would be "N123" and "N123".
>
> Since the generated id is always a name token, and the name
> token can never
> have a space character, the space is an effective delimiter
> to guarantee
> uniqueness.
>
> I hope this helps.
>
> ..................... Ken
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