question with using Muenchian/xsl:key (Re: sort/group/count problem)

["Xu, Xiaocun" <XXu at CommercialWare dot com>]

Hi,

  Thanks to Jeni's suggestion, I started to apply Muenchian for grouping.
It works well, but I have one problem: since xsl:key is top-level element, I
can not seem to apply element scope with it.
  The XML structure I have is:
      <itemlist>
	<item itemid="Z101" units="1"/>
	<item itemid="Z102" units="2"/>
	<item itemid="Z101" units="4"/>
      </itemlist>
      <itemlist>...
What I need is for each itemlist, print out all unique itemids and the sum
of their units attribute.

The following is what I have in my XSL right now:
<xsl:key name="items-by-itemid" match="item" use="@itemid"/>
<xsl:template match="itemlist">
  <xsl:for-each select="item[count(. | key('items-by-itemid', @itemid)[1]) =
1]">
    <xsl:sort select="@itemid" />
      <tr>
        <td><xsl:value-of select="@itemid"/></td>
	<td><xsl:value-of
select="sum(key('items-by-itemid',@itemid)/@units)"/></td>
      </tr>
  </xsl:for-each>
</xsl:template>

key('items-by-itemid', @itemid) returns all items with the same @itemid in
the entire XML document.  I just want all items with the same @itemid in
each of the itemlist element, how can I do that?

Much thanks,
Xiaocun Xu
xxu@commercialware.com


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