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RE: rendering Xlink from a XML by using XSL
- To: <xsl-list at mulberrytech dot com>
- Subject: RE: rendering Xlink from a XML by using XSL
- From: "Handren Ahmed" <handren at chello dot se>
- Date: Fri, 10 Nov 2000 11:59:40 +0100
- Reply-To: xsl-list at mulberrytech dot com
hi!
That was exactly what I meant!
I did write following code but it doesn't work either.
In my xml file I wrote:
<Adress xlink:type="simple" xlink:href="http://www.dsv.su.se"
xlink:show="new"
xmlns:xlink="http://www.w3.org/TR/xlink/"
>Klick here</Adress>
In my xsl file I try to show that link by writing the follwing code:
<xsl:template match="*[@xlink:href]">
<xsl:value-of select="."/>
</xsl:template>
How can I use Xlink? How can I click on the xlink:-)? I'am very confused.
By the way,what is the purpose of copying the whole XML-file by using a XSL.
Dont you get the same xml file? Why not send over the whole xml-file?
Thank you
Handren A
-----Original Message-----
From: owner-xsl-list@mulberrytech.com
[mailto:owner-xsl-list@mulberrytech.com]On Behalf Of Eric van der Vlist
Sent: den 9 november 2000 13:27
To: xsl-list@mulberrytech.com
Subject: Re: rendering Xlink from a XML by using XSL
Handren Ahmed wrote:
> I would like to use xlink in an applikation, witch I write in XSL. All my
> tries has been faild so far. Anyone could help me out please.
I am not sure that it's what you mean, but I have recently written an
article [1] showing how one can expand links from several linking
technologies (including XLink) with XSLT.
Hope this helps.
Eric
[1] http://www.xml.com/pub/2000/10/04/linking/index.html
--
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Eric van der Vlist Dyomedea http://dyomedea.com
http://xmlfr.org http://4xt.org http://ducotede.com
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