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RE: Tricky problem, limiting the number of source elements processed.
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: RE: Tricky problem, limiting the number of source elements processed.
- From: Kay Michael <Michael dot Kay at icl dot com>
- Date: Wed, 25 Oct 2000 10:00:17 +0100
- Reply-To: xsl-list at mulberrytech dot com
If the <typeA> elements precede the <typeB>s, can't you just write
<xsl:for-each select="(typeA | typeB)[position() < 6]">
?
Mike Kay
>
> I am having difficulties figuring out how to do this, so any
> help is greatly
> appreciated.
>
> Lets say you have two types of elements, "typeA" and "typeB"
> that you want
> to display, but you only want to display a maximum number of
> them, say five.
> More particularly, you want to display as many of typeA as
> possible, up to
> the limit of five, but if there are less than five typeAs,
> the remaining
> space should be filled with typeBs.
>
> So if you have say:
> <typeA>A1</typeA>
> <typeA>A2</typeA>
> <typeA>A3</typeA>
> <typeA>A4</typeA>
> <typeB>B1</typeB>
> <typeB>B2</typeB>
> <typeB>B3</typeB>
>
> , that is 4 typeAs and 3 typeBs, you would get:
>
> A1, A2, A3, A4, B1.
>
> as there is one space remaining for a typeB element.
>
> Thanks.
>
>
>
>
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>
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