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RE: XSL attribute expression
- To: <xsl-list at mulberrytech dot com>
- Subject: RE: XSL attribute expression
- From: "Don Hill" <dhill at veriomail dot com>
- Date: Wed, 4 Oct 2000 21:29:16 -0500
- Reply-To: xsl-list at mulberrytech dot com
Dwight,
Try something like this
<a><xsl:attribute name="href" ><xsl:value-of
select="{url}"/></xsl:attribute></a>
-Don
-----Original Message-----
From: owner-xsl-list@mulberrytech.com
[mailto:owner-xsl-list@mulberrytech.com]On Behalf Of Dwight Kelly
Sent: Wednesday, October 04, 2000 6:34 PM
To: xsl-list@mulberrytech.com
Subject: XSL attribute expression
I am fairly new to XSL and am trying to extract the value of the attribute
'url' from the node 'job' and make it a HTML <A HREF=> link. Is this the
correct syntax? Instead of getting
<A HREF="http://www.apago.com/jobs/1">URL</A>
I am getting
<A HREF="{@url}">URL</A>
here is my xml file fragment:
<job job-id="100" url="http://www.apago.com/jobs/1" />
and my xsl fragment:
<xsl:template match="job">
<DIV>
Job <xsl:value-of select="@job-id" />
<A HREF="{@url}">URL</A>
</DIV>
</xsl:template>
Thanks,
--
Dwight Kelly
Apago, a division of Essential Technical Services, Inc.
315 Allen Street Cumming, GA 30040
voice:(770) 889-2848 fax:(770) 889-2624 Internet:dkelly@apago.com
http://www.apago.com
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