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selecting then conditional test
- To: <XSL-List at mulberrytech dot com>
- Subject: selecting then conditional test
- From: "Jason Thomas" <jason dot thomas at plexus dot com>
- Date: Wed, 4 Oct 2000 11:08:50 -0600
- Reply-To: xsl-list at mulberrytech dot com
I'm new at xml but after looking through the help and FAQs I still can't
figure this out. I'm trying to remove duplicates from a list, sort it, and
also check for other things not to display.
My xml is as follows:
<alljobs>
<job>
<item1>two</item1>
...
</job>
<job>
<item1>one</item1>
...
</job>
<job>
<item1>two</item1>
...
</job>
<job>
<item1>N/A</item1>
...
</job></alljobs>
What I want to do is display a sorted list without duplicates and without
the N/A like so:
one
two
My xsl is as follows:
<xsl:template match="alljobs">
<xsl:for-each select="job/item1[not(.=following::job/item1)]">
<xsl:sort/>
<xsl:if test="ancestor::job/item1!='N/A'">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
I've also tried: <xsl:if test="//item1!='N/A'">
Unfortunately these don't work. I eliminate the duplicates and sort it but
the if statement doesn't work. What am I doing wrong? Thanks for your help!
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