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counting leaf nodes
- To: xsl-list at mulberrytech dot com
- Subject: counting leaf nodes
- From: Perry Roland <pdr4h at unix dot mail dot virginia dot edu>
- Date: Wed, 30 Aug 2000 11:02:58 -0400
- Reply-To: xsl-list at mulberrytech dot com
Hi,
I need some help with an expression that will count the leaf
nodes on a given branch. Let's say I have XML like
<su><!-- top level -->
<su><!-- 2nd level -->
<su><!-- 3rd level -->
<su><!-- 4th level --></su>
<su><!-- 4th level --></su>
<su><!-- 4th level --></su>
</su>
</su>
<su><!-- 2nd level -->
<su><!-- 3rd level --></su>
<su><!-- 3rd level --></su>
<su><!-- 3rd level --></su>
</su>
</su>
My goal is to be able to output this as an HTML table like
<TABLE BORDER=1>
<TR><TD COLSPAN=6>*</TD></TR> <!-- top level -->
<TR><TD COLSPAN=3>*</TD><TD COLSPAN=3>*</TR> <!-- 2nd level -->
<TR><TD COLSPAN=3>*</TD><TD>*</TD><TD>*</TD><TD>*</TD></TR> <!-- 3rd level -->
<TR><TD>*</TD><TD>*</TD><TD>*</TD></TR> <!-- 4th level -->
</TABLE>
As I process each su element, in order to calculate the COLSPAN
attribute, I need to know how many su elements there are below the
current one that don't have su children themselves.
Any help is appreciated.
--
perry
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